Consider the function f(x) = x2 + 12x + 11. x-intercepts: 0 = x2 + 12x + 11 0 = (x + 1)(x+ 11) y-intercept: f(0) = (0)2 + 12(0) + 11 What are the intercepts of the function? The x-intercepts are . The y-intercept is .

Answer:The coordinates of the x-intercepts are;(-1, 0) and (-11, 0)The coordinate of the y-intercept is;(0, 11)Step-by-step explanation:The given function is f(x) = x² + 12·x + 11The x-intercept is at f(x) = 0 which gives;0 = x² + 12·x + 11 which has been factored as (x + 1)(x+11) such that we have;(x + 1)(x+11) = 0x  = -1, or x = -11The y-intercept occurs at x = 0, we therefore have;f(0) = (0)² + 12·(0) + 11 = 11Therefore, we have f(0) = 11 = YGiven that at the x-intercept, y = 0, then the coordinates of the x-intercepts are;(-1, 0) and (-11, 0)Given that at the y-intercept, x = 0, then the coordinate of the y-intercept is;(0, 11).