Solve this system of equations by elimination:8x+9y=4812x+5y=21
Accepted Solution
A:
Answer:Let's solve your system of equations by elimination.
8x+9y=48;12x+5y=21
Steps:
Multiply the first equation by 5,and multiply the second equation by -9.
5(8x+9y=48)
−9(12x+5y=21)
Becomes:
40x+45y=240
−108x−45y=−189
Add these equations to eliminate y:
−68x=51
Then solve−68x=51for x:
−68x
/−68
=
51
/−68 (Divide both sides by -68)
x= −3
/4
Now that we've found x let's plug it back in to solve for y.
Write down an original equation:
8x+9y=48
Substitute
−3
/4
8x+9y=48:
8(
−3
/4
)+9y=48
9y−6=48 (Simplify both sides of the equation)
9y−6+6=48+6 (Add 6 to both sides)
9y=54
9y
/9 = 54
/9 (Divide both sides by 9) y=6
Answer: x= −3
/4 and y=6Hope This Helps! Have A Nice Day!!